Entry of Woods hex (roads and path) question

[Jon]

Hi

Look at the first Example for A4.132

Assume an Infantry unit in H2. It uses bypass movement along the I3-H3 hexside for 1MF. What then is its MF cost to enter I4

I always took at as costing 2MF, since I4 is a woods hex that contains a road [B13.1], and it costs Infantry 2MF to enter a woods hex unless entry is made via a road hexside [B13.4 & A4.132]. In the move I describe above, movement from bypass of the I3-H3 hexside into I4 is not entering I4 via a road hexside, since I3 is the hex being bypassed.

However I have had it put to me that the move described would only cost 2MF, 1 in bypass along the I3-H3 hexside and 1 to enter I4.

Who is correct?

Another situation is a unit in 10C3. It uses bypass in D3, along the D3-C4 & D3-D4 hexsides for 1 MF. What then is its cost to enter E4
I say another 2MF , since from its bypass, it would not be entering E4 across a path hexside. However it was put to me that it could use the path to enter E4 for 1MF.

Thoughts

Cheers
Jon

[Swiftandsure]

You are right about the first situation.
The bypassing unit is IN I3, and will cross the I3-I4 hexside to enter I3, which is not a road hexside. So the entry cost will be 2MF (for a total move bypass entry of 3 MF).

In the second case, the bypassing unit is considered to be in D3. There is no path across the D3-E4 hexside, so the cost to enter E4 is 2MF.

http://img359.imageshack.us/img359/580/10bypassut7.png
The important thing to realise here is that a unit which bypasses an obstacle is in the hex of the obstacle and not "straddling" the hexside it is moving along.
In the second case, if there was a building in D4, and a unit bypassed it, it could enter E4 using the path, as there is a path connecting D4 to E4.